Answer:
[tex] \dfrac{2x}{x + 7} [/tex]
Step-by-step explanation:
[tex] \dfrac{4x^2 - 16x}{2x^2 + 6x - 56} = [/tex]
Factor the numerator and denominator.
[tex]= \dfrac{4x(x - 4)}{2(x^2 + 3x - 28)}[/tex]
[tex]= \dfrac{4x(x - 4)}{2(x + 7)(x - 4)}[/tex]
[tex] = \dfrac{2x}{x + 7} [/tex]
