Given :
A right angle triangle ABC .
To Find :
The perimeter of ABC .
Solution :
Since, triangle ABC is right angled and angle ∠ABC is 46° .
So, AC = AB cos 46° = 7.64 units.
Also, CB = AB sin 46° = 7.91 units.
Therefore, the perimeter of ΔABC is :
P = 11 + 7.64 + 7.91 units
P = 26.55 units
Hence, this is the required solution.
