Answer:
(1,-2)
Step-by-step explanation:
[tex]y = {x}^{2} - 2x - 1 \\ equation \: is \: in \: the \: form \: a {x}^{2} + bx + c \\ a = 1 \\ b = - 2 \\ c = - 1 \\ solve \: for \: x \\ x = \frac{ - b}{2a} = \frac{ - ( - 2)}{2 \times 1} = \frac{2}{2} = 1 \\ subsitute \: x = 1 \:in \: the \: original\: equation \\ y = {1}^{2} - (2 \times 1) - 1 = - 2[/tex]
