Step-by-step explanation:
the equation of the circle centered at (-3, – 10)
=> (x+3)²+(y+10)²=2²
<=> x²+6x+9+y²+20y+100=4
x²+y²+6x+20y+105=0
Let's see
[tex]\\ \rm\dashrightarrow (x-h)^2+(y-k)^2=r^2[/tex]
[tex]\\ \rm\dashrightarrow (x+3)^2+(y+10)^2=2^2[/tex]
[tex]\\ \rm\dashrightarrow (x+3)^2+(y+10)^2=4[/tex]
[tex]\\ \rm\dashrightarrow x^2+y^2+6x+20y+105=0[/tex]
