Respuesta :

mhanifa

Answer:

  • See https://brainly.com/question/23882263 for A and B parts of the first question

d)

  • [tex]HF = \sqrt{EH^2+EF^2} = \sqrt{2^2+3^2} = \sqrt{13}[/tex]

#2

  • [tex]d = \sqrt{2^2+5^2} = \sqrt{4+25} = \sqrt{29}[/tex]

#3

Diagonals are perpendicular. Side length of the rhombus:

  • [tex]a = \sqrt{(8/2)^2+(6/2)^2} = \sqrt{4^2+3^2} = \sqrt{25} = 5[/tex]

Perimeter:

  • P = 4a = 4(5) = 20

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