Answer:
The required volume is 0.84 L
Explanation:
Given,
Mass of O2 gas = 1.20 g
We know,
At STP, molar volume of all gases is 22.4 L
and Molar mass of O2 gas is 32 g
Now,
Number of moles = mass/molar mass
= 1.20/32
= 0.0375
Again,
At STP,
Number of moles = Volume/Molar volume
or, Volume = Number of moles X Molar Volume
or Volume = 0.0375 X 22.4
∴ Volume = 0.84 L
So, the required volume is 0.84 L
