Answer:
The electric field experienced by the charge is 1.248 x 10¹⁹ N/C
Step-by-step explanation:
Given;
the magnitude of the force, F = 2 N
the magnitude of the charge, q = 1.602 x 10⁻¹⁹ C
The electric field experienced by the charge is calculated as follows;
[tex]E = \frac{F}{q} \\\\E = \frac{2}{1.602 \times 10^{-19} \ } \\\\E = 1.248 \times 10^{19} \ N/C[/tex]
Therefore, the electric field experienced by the charge is 1.248 x 10¹⁹ N/C.
