Answer: 1.15 s
Explanation:
Given
Height of rock h=6.5 m
The horizontal speed of tiger u=3.5 m/s
In the vertical direction, there is no initial speed
Using the equation of motion
[tex]\Rightarrow h=ut+\frac{1}{2}at^2\\\\\Rightarrow 6.5=0+\frac{1}{2}\times 9.8\times t^2\\\\\Rightarrow t=\sqrt{\dfrac{13}{9.8}}=1.15\ s[/tex]
Time taken is 1.15 s
