Answer:
[tex]2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}[/tex]
Explanation:
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In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:
[tex]2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}[/tex]
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