Answer:
the first four terms are 0,0,2,6
Step-by-step explanation:
The computation of the first four terms of the sequence is shown below:
Given that
f(n) = (n - 1) (n -2)
= n^2 - 2n - n + 2
= n^2 - 3n + 2
Now the first four terms are
f(1) = 1^2 - 3(1) + 2
= 1 - 3 + 2
= 0
f(2) = 2^2 - 3(2) + 2
= 4 -6 + 2
= 0
f(3) = 3^2 - 3(3) + 2
= 9 - 9 + 2
= 2
f(4) = 4^2 - 3(4) + 2
= 16 - 12 + 2
= 18 - 12
= 6
So, the first four terms are 0,0,2,6
