Answer:
50 N
Explanation:
We are given;
Force on larger piston; F2 = 5000 N
Ratio of diameter of smaller piston to larger piston = 1:10
Now, formula for force on smaller piston which we will denote with F1 is gotten from;
F1 = F2 × A1/A2
Now, A1 = π(d1)²/2
A2 = π(d2)²/2
Thus:
F1 = F2 × (π(d1)²/2)/(π(d2)²/2)
This gives;
F1 = F2 × (d1/d2)²
Plugging in the relevant values;
F1 = 5000 × (1/10)²
F1 = 50 N
