Answer:
Explanation:
2 min 20 sec = 140 sec .
In 40 sec one round
In 140 sec 140 / 40 round = 3.5 round .
That means the boy will be positioned at the diametrically opposite corner of the square path .
side of square path = 15 m
length of diameter = 15√2
= 21.21 m
Displacement of boy is 21.21 m .
