Answer:
Step-by-step explanation:
To put the equation into vertex form, we need to complete the square
[tex]g(x) = (x^2 - 4x + ...) - 1\\g(x) = (x^2-4x+(\frac{4}{2})^2 ) - 1 - (\frac{4}{2})^2 \\g(x) = (x-2)^2 - 5\\[/tex]
This is in the form
[tex]y = a(x-h)^2 + k\\(h, k)[/tex]
So, the vertex is (2, -5)
and [tex]g(x) = (x-2)^2-5[/tex]
