Answer:
x²+8x=0
⇒a=1 b=8 c=0
Δ=b²-4ac
Δ=8²-4.1.0
Δ=8²
Now you solve the bhaskara formula:
x=-b±[tex]\sqrt{}[/tex]Δ/2a
x=-8±8/2
x1=0
x2= -8
hope this helps.
