contestada

Find a counterexample to disprove the conjecture.
Conjecture
AB
divides CAD into two angles. So, AB is an angle bisector of ZCAD.
m ZCAB = 20° andm ZDAB = 20°
m ZCAB = 20° andm ZCAD = 40°
m LDAB = 60° and m LCAD = 120°
mZCAB = 70° andm LDAB = 20°

Respuesta :

olayemiolakunle65

Answer:

D. mZCAB = 70° and mLDAB = 20°

Step-by-step explanation:

An angle bisector is a line that divides a given angle into two equal parts. From the given question:

if angle CAD is divided into two unequal angles by AB, then AB is not an angle bisector of ZCAD.

For example: let mCAD = [tex]90^{o}[/tex]. Then if mCAB = mDAB = [tex]45^{o}[/tex], then AB is an angle bisector.

But if mCAB [tex]\neq[/tex] mDAB, then AB is not an angle bisector. Eg: mZCAB = 70° and mLDAB = 20°

Answer:

f

Step-by-step explanation:

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