Answer:
250 m
Explanation:
Given :
Initial velocity, u = 0
Acceleration, a = 5 m/s2
Time elapsed is t = 10 seconds
The distance traveled in 10 seconds by the particle when accelerating at 5 m/s2 is given by,
[tex]$ x = ut+\frac{1}{2}at^2$[/tex]
Putting the values,
[tex]$ x = 0\times 10+\frac{1}{2}(5)(10)^2$[/tex]
[tex]$ x =\frac{1}{2}(5)(100)$[/tex]
x = 250 m
The particle moved 250 m in 10 seconds
