Let f(x) = y
y = log3(x+1) - 1
Plug x in y and y in x
x = log3(y+1) - 1
x + 1 = log3(y+1)
3^(x+1) - 1 = y
[tex]y = 3^{x+1}[/tex] - 1
This is the inverse function.
Hope it helps! xxxx
Answer:
y = [tex]3^{(x+1)}[/tex] -1
Step-by-step explanation:
x = [tex]log_{3}[/tex](y + 1) - 1
x + 1 = log₃(y + 1)
[tex]3^{(x+1)}[/tex] = y + 1
[tex]3^{(x+1)}[/tex] -1 = y
