Answer:
The correct option is;
[B] ΔABF ≅ ΔEDF
Step-by-step explanation:
GIven that ∠FAE is congruent to ∠FEA
Therefore, triangle ΔFAE is an isosceles triangle (Definition of isosceles triangle)
Segment FA is equal to segment FE (Equal segments of isosceles triangle)
Angle ∠EFD is congruent to angle ∠AFB (Vertically opposite angles)
Therefore, triangle ΔABF is congruent to triangle ΔEDF (Angle Angle Side AAS rule of congruency)
The correct option is ΔABF ≅ ΔEDF.
