tbird1270 tbird1270

01-08-2020
Mathematics

contestada

Compute the values of dy and Δy for the function y=e^(2x)+6x given x=0 and Δx=dx=0.03.

Respuesta :

sqdancefan sqdancefan

01-08-2020

Answer:

dy = 8·dx
Δy = 0.24

Step-by-step explanation:

The derivative of your function is ...

y' = dy/dx = 2e^(2x) +6

At x=0, the value is ...

y'(0) = 2e^0 +6 = 8

dy = 8·dx

__

Δy = y'(0)·Δx

Δy = 8(.03)

Δy = 0.24

Answer Link

Otras preguntas

After we fought England, we acted in ___________ way. We basically opposed anything they supported.

What vapor pressure of a liquid

Does anybody know this pleasee it would help a lot!!

how is thermal energy apart of weather changing

Look at the word below and select the prefix. preexisting exist exist pre pre ing ing

Solve -4<3x+2≤5 A.) x>-2 or x≤1 B.) x>2 and x≤2 C.) x>2 or x≤1 D.) x>-2 and x≤1

turn 311/34 to a mixed number

5/11 of 132 meters .

MS World History A (Voekel) / Week 11 (10/25 10/29) 14. Explain the idea of the Incan community storehouses. What were they and what was its purpose

how do I solve 16−(−5)=3(7−2)