Answer:
The answer is B.
Step-by-step explanation:
You have to substitute x = 2, into the equation of y :
[tex]y = 6 {x}^{3} - 5 {x}^{2} + 4x - 3[/tex]
[tex]let \: x = 2[/tex]
[tex]y = 6 {( 2)}^{3} - 5 {(2)}^{2} + 4(2) - 3[/tex]
[tex]y = 48 - 20 + 8 - 3[/tex]
[tex]y = 33[/tex]
