Answer:
Step-by-step explanation:
[tex]g^{-1} (-3)=7\\[/tex]
let h(x)=y
y=2x-3
flip x and y
x=2y-3
2y=x+3
[tex]y=\frac{1}{2}(x+3)\\or~h^{-1}(x)=\frac{1}{2}(x+3)\\(h^{-1} oh)(x)=h^{-1}(h(x))=h^{-1}(2x-3)=\frac{1}{2}(2x-3+3)=\frac{1}{2}(2x)=x\\(h^{-1}oh)(1)=1[/tex]
