Respuesta :

SvetkaChem

Answer:

Na3PO4 is excess reactant, CaCl2 is limiting reactant.

Explanation:

                                      3CaCl2 + 2Na3PO4 ---> Ca3(PO4)2 + 6NaCl

from reaction :              3 mol        2 mol

given:                            6 mol         5 mol (X)

X = (6*2)/3 = 4 mol Na3PO4

For 6 mol CaCl2 we need 4 mol Na3PO4, but  we have 5 mol Na3PO4,

Na3PO4 is excess reactant, so CaCl2 is limiting reactant.

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