Answer:
x = [tex]y^{2}[/tex] - 4y + 12
Step-by-step explanation:
y = 2 + [tex]\sqrt{x-8}[/tex]
Put the 2 on the other side
y - 2 = [tex]\sqrt{x-8}[/tex]
Square both sides
[tex](y-2)^{2}[/tex] = x - 8
Expand the brackets
[tex]y^{2}[/tex] - 4y + 4 = x-8
Move 8 to the other side
x = [tex]y^{2}[/tex] - 4y + 12
