Answer:
(10x - 5) square units.
Step-by-step explanation:
Let the lengths of equal sides be x units.
Hence, AB + AD + DC = x + x + x = 3x
Therefore, BC = 3x - 2
[tex]Area \: of \: trapezoid \\ = \frac{1}{2} (AD + BC) \times 5 \\ = \frac{1}{2} (x + 3x - 2) \times 5 \\ = \frac{1}{2} (4x - 2) \times 5 \\ = \frac{1}{2} \times 2 (2x - 1) \times 5 \\ = (2x - 1) \times 5 \\ = (10x - 5) \: {units}^{2} [/tex]
