Answer:
[tex]B.\ (-1.4z+0.4)\times 40 \\\\D.\ (8z-4)(-7)[/tex]
Step-by-step explanation:
Given the expression:
[tex]-56z+28[/tex]
#We introduce a bracket and a common divisor:
Since 7 is a divisor of both numbers, we rewrite the expression as:
[tex]-56z+58=-7(8z-4)\\\\=(8z-4)(-7)[/tex]
#We then introduce a second common divisor, 40:
[tex]-56z+28=\frac{1}{40}\times-56z+28\times \frac{1}{40}\\\\=40(-1.4z+0.7)[/tex]
Hence, the expression can be rewritten as 40(-1.4z+0.4) and (8z-4)(-7)
