Line II
2x+3y=-5
3y=-2x-5
y=[tex] \frac{-2}{3} x- \frac{5}{3} [/tex]
Gradient m= [tex] \frac{-2}{3} [/tex]
Gradient of line I will be;
[tex] \frac{-2}{3} *m=-1[/tex]
m=[tex] \frac{3}{2} [/tex]
Equation of line I;
y=mx+c
y=[tex] \frac{3}{2} x+c[/tex]
Finding value of c by replacing for;
y=1
x=-6
1=[tex] \frac{3}{2} *(-6)+c[/tex]
c=10
y=[tex] \frac{3}{2} x+10[/tex]
