Answer:
Initial Ecell = 0.78V
Explanation:
From the question, we get;
(Cd)2+) + Mn ---> Cd + (Mn2+)
We will check half cell potentials from the table attached, we get ;
Mn = - 1.18V and Cd = - 0.4V
Ecell (standard) = E(reduction) - E(oxidation) = - 0.4 - (-1.18) = 0.78V
