HotaroKim
HotaroKim HotaroKim
  • 02-03-2020
  • Physics
contestada

A lightbulb consumed 1100J in 30 minutes. Find Power, resistance, and calculate energy in kWh

Respuesta :

MathPhys
MathPhys MathPhys
  • 02-03-2020

Explanation:

30 minutes is 1800 seconds.

Power = energy / time

P = 1100 J / 1800 s

P = 0.611 W

Converting the energy from J to kWh:

1100 J × (1 Ws / 1 J) × (1 kW / 1000 W) × (1 h / 3600 s) = 3.06×10⁻⁴ kWh

To find resistance, you need to be given either the voltage or the current.

Answer Link

Otras preguntas

what is the sum of 15 and x is greater than or equal to 12 minus y
What were some of the successes of napoleon iii's second empire?
marco has a jug with 3 7/2 ounces of juice. he wants to use some small cups to pass out samples of the juice each cup can hold 2 1/2 ounces of juice. how many
Write to explain 44 - 9
PLEASE MATH HELP WILL GIVE BRAINLIEST What is the value of y?
Which method should be used to solve for x? 2.5x = 5.7 A. distributive property B. addition property of equality C. combining like terms D. division property of
Jack's mother gave him 50 chocolates to give to his friends at his birthday party. he gave 3 chocolates to each of his friends and still had 2 chocolates left.
The bottom of a box has a surface area of 25.0 cm 2 . The mass of the box is 34.0 kilograms. Acceleration due to gravity at sea level is 9.80 m/s 2 . What press
please help me out I'm really confused
Graph the system of equations on your graph paper to answer the question. y= -x + 4 y= x - 2 What is the solution for the system of equations? Enter your answer