Answer:
D
Step-by-step explanation:
The function will be zero when the numerator is equal to 0. So, set the numerator equal to 0 and solve:
[tex]0 = 4 {x}^{2} - 36x[/tex]
I will use the quadratic formula:
[tex] \frac{ 36 + \sqrt{ {36}^{2} - 4(4)(0)} }{2(4)} \\ \frac{ 36 + 36}{8} = 9[/tex]
Therefore, x = 9 is a 0. Let's check with subtracted root now:
[tex] \frac{ 36 - \sqrt{ {36}^{2} - 4(4)(0)} }{2(4)} \\ \frac{ 36 - 36}{8} = 0[/tex]
It appears 0 is also a root.
Therefore, the answer is D.
