Answer:
two real solution
Step-by-step explanation:
x^2 + 10x − 25 = 0
we can solve this by finding out the value of x
lets assume the equation is a\times x^{2}+b\times x+c=0
x=-b\pm \sqrt{(b^{2}-4ac)}\div 2a
x=-10\pm\sqrt{100+4*25}\div2
x=-5\pm5\sqrt2
then we get both real value of x
so two real solution
