For this case we must find the value of "x" that meets the following equation:
[tex]\frac {4} {3} = x + \frac {10} {15}[/tex]
We subtract [tex]\frac {10} {15}[/tex] on both sides of the equation:
[tex]\frac {4} {3} - \frac {10} {15} = x\\\frac {15 * 4-3 * 10} {3 * 15} = x\\\frac {60-30} {45} = x\\- \frac {30} {45} = x[/tex]
We simplify:
[tex]x =\frac {6} {9}=\frac{2}{3}[/tex]
Finally, [tex]x =\frac {2} {3}[/tex]
Answer:
[tex]x =\frac {2} {3}[/tex]
