Answer:
[tex]x^{12}*y^6[/tex]
Step-by-step explanation:
We know that [tex](a*b)^{m}=a^{m}*b^{m}[/tex]
Given [tex](x^{4}*y^{4})^{3}[/tex]
here a=[tex]x^{4}[/tex] and b=[tex]y^{4}[/tex]
by using the above principle we get
[tex](x^{4}*y^{4})^{3}[/tex]=[tex](x^{4})^{3}*(y^{2})^{3}[/tex]
We know that [tex](a^{m})^{n}=a^{mn}[/tex]
[tex](x^{4}*y^{4})^{3}[/tex]=[tex]x^{4*3}*y^{2*3}[/tex]=[tex]x^{12}*y^6[/tex]
