Answer: 2, 3, 6, 11, 18, 27
Step-by-step explanation:
Plug the x-value into the equation y = (x)² + 2 to solve for the y-value.
[tex]\begin{array}{c|l||c}\underline{\quad x\quad }&\underline{(x)^2+2=}&\underline{\quad y\quad}\\0&(0)^2+2=&2\\1&(1)^2+2=&3\\2&(2)^2+2=&6\\3&(3)^2+2=&11\\4&(4)^2+2=&18\\5&(5)^2+2=&27\end{array}[/tex]
