wilkinsonei9959 wilkinsonei9959
  • 02-09-2019
  • Chemistry
contestada

If 14.5 kJ of heat were added to 485 g of liquid water, How much would its temperature increase?

Respuesta :

RomeliaThurston RomeliaThurston
  • 05-09-2019

Answer: The increase in temperature is 7.14°C

Explanation:

To calculate the change in temperature, we use the equation:

[tex]q=mc\Delta T[/tex]

where,

q = heat absorbed = 14.5 kJ = 14500 J    (Conversion factor: 1 kJ = 1000 J)

m = mass of water = 485 g g

c = specific heat capacity of water = 4.184 J/g.°C

[tex]\Delta T[/tex] = change in temperature = ?

Putting values in above equation, we get:

[tex]14500J=485g\times 4.184J/g.^oC\times \Delta T\\\\\Delta T=7.14^oC[/tex]

Hence, the increase in temperature is 7.14°C

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