Answer:
Step-by-step explanation:
To find Laplace transform of [tex]t^2e^4^t[/tex]
We know that Laplace transform for
[tex]t^n e^{at}[/tex] is
[tex]\frac{n!}{(s-a)^{n+1} }[/tex], for all n = 1,2,3.... and real values a..
Here n =2 and a=4
Hence substituting we get
Laplace transform of given term is
[tex]\frac{2!}{(s-4)^{2+1} } \\=\frac{2}{(s-4)^3}[/tex]
