Answer: [tex]\bold{d)\quad y = 3 cos (\dfrac{4}{3}x-2\pi) + 2}[/tex]
Step-by-step explanation:
[tex]\text{Period = }\dfrac{2\pi}{B}\\\\\\\dfrac{1}{2}\text{Period = }\dfrac{1}{2}\cdot \dfrac{2\pi}{B}\quad =\dfrac{2\pi}{2B}\\\\\\\text{In the given equation, B = }\dfrac{2}{3}\implies 2B=\dfrac{2\cdot 2}{3}\quad =\dfrac{4}{3}\\[/tex]
The only option that has B = 4/3 is the last one.
