Answer:
[tex]\frac{-2x-12}{x^2-16}[/tex]
Step-by-step explanation:
We want to find the difference;
[tex]\frac{x}{x^2-16}-\frac{3}{x-4}[/tex]
The first denominator can be rewritten as;
[tex]x^2-16=(x+4)(x-4)[/tex]
Therefore the least common denominator is [tex]x^2-16[/tex]
We collect LCD to obtain;
[tex]\frac{x-3(x+4)}{x^2-16}[/tex]
Expand the parenthesis to obtain;
[tex]\frac{x-3x-12}{x^2-16}[/tex]
[tex]\frac{-2x-12}{x^2-16}[/tex]
