The point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
We have the slope m = 4 and tthe point (-3, -1). Substitute:
[tex]y-(-1)=4(x-(-3))\\\\y+1=4(x+3)\qquad|\text{use distributive property}\\\\y+1=4x+12\qquad|-1\\\\y=4x+11\qquad|-11\\\\y-11=4x\qquad|-y\\\\4x-y=-11[/tex]
Answer:
point-slope form: y + 1 = 4(x + 3)
slope-intercept form: y = 4x + 11
standard form: 4x - y = -11
