We want to solve
[tex]\frac{2}{5}\le x-4[/tex]
We need to clear the fraction first by multiplying through with the LCM, which is 5.
[tex]5\times \frac{2}{5}\le 5x-5\times4[/tex]
[tex]2\le 5x-20[/tex]
Grouping like terms gives,
[tex]2+20 \le 5x[/tex]
[tex]\Rightarrow 22 \le 5x[/tex]
Dividing through by 5 gives,
[tex]\frac{22}{5} \le x[/tex]
We can rewrite this as
[tex]x\ge \frac{22}{5}[/tex]
OR
tex]x\ge 4\frac{2}{5}[/tex]
