Respuesta :

tramserran

2(x + 3) ≥ -10 - 4x

2x + 6 ≥ -10 - 4x

+4x               +4x

6x + 6 ≥ -10

      -6   -6  

6x       ≥ -16

      [tex]\frac{6x}{6} \geq \frac{-16}{6}[/tex]

      [tex]x \geq -\frac{8}{3}[/tex]        reduced fraction

choixongdong

2(x+3) greater than or equal to -10 - 4x

So

2(x+3) >= -10 - 4x

2x + 6 >= -10 - 4x

2x + 4x >= -10 - 6

6x >= - 16

 x >= - 16/6

 x >= - 8/3

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