Respuesta :

olemakpadu
The zeros of y = 3x^2+3x  means to solve for the values of x when y = 0

 y = 3x²+ 3x =0

y = 3x²+3x  = 0

3x²+3x  = 0                  Factorize

3x(x + 1) = 0

3x = 0,  or (x + 1) = 0

From 3x = 0,  x = 0/3 =0

From (x + 1) = 0,  x = 0 -1 = -1.

Therefore the zeros are 0 and -1.

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